CUET · MATHS · PYQ PAPER 2025
A man is known to speak truth 3 out of 4 times. He throws a die and reports that it is four. The probability that it is actually four is :
- A \(\frac{1}{3}\)
- B \(\frac{7}{8}\)
- C \(\frac{3}{8}\)
- D \(\frac{1}{8}\)
Answer & Solution
Correct Answer
(C) \(\frac{3}{8}\)
Step-by-step Solution
Detailed explanation
\( P(\text{actual four}) = \frac{1}{6} \) \( P(\text{not actual four}) = \frac{5}{6} \) \( P(\text{man speaks truth}) = \frac{3}{4} \) \( P(\text{man lies}) = \frac{1}{4} \) \( P(\text{reports 4 | actual 4}) = P(\text{truth}) = \frac{3}{4} \)…
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