CUET · MATHS · PYQ PAPER 2023
A linear programming problem is as follows:
Maximize/minimize objective function \(z=2 x-y+5\) subject to constraints:
\(3 x+4 y \leq 60, \quad x+3 y \leq 30, \quad x \geq 0, y \geq 0 .\)
If the corner points of feasible region are \(A(0,10), B(12,6), C(20,0), O(0,0)\), then which of the following is true:
- A Maximum value of \(z\) is 40
- B Minimum value of \(z\) is -5
- C Difference of maximum and minimum values of \(z\) is 35
- D At two corner points value of \(z\) are equal
Answer & Solution
Correct Answer
(B) Minimum value of \(z\) is -5
Step-by-step Solution
Detailed explanation
At \(A(0,10): z = 2(0) - 10 + 5 = -5\) At \(B(12,6): z = 2(12) - 6 + 5 = 23\) At \(C(20,0): z = 2(20) - 0 + 5 = 45\) At \(O(0,0): z = 2(0) - 0 + 5 = 5\) Minimum value of \(z\) is -5.
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