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CUET · MATHS · PYQ PAPER 2025

A furniture trader deals in only two items - chairs and tables.
He has Rs. 50, 000 to invest and a space to store at most 35 items.
A chair costs Rs. 1000 and a table costs Rs. 2000.
The trader earns a profit of Rs. 150 on a chair and Rs. 250 on a table.
Choose the correct option that describes the given linear programming problem (LPP) to maximize the profit, where \(x\) and \(y\) are the number of chairs and tables.

  1. A Maximize \(Z=150 x+250 y\),
    Subject to constraints,
    \(x+y \leq 35, x+2 y \geq 50, x \geq 0, y \geq 0\)
  2. B Maximize \(Z=150 x+250 y\),
    Subject to constraints,
    \(x+y \leq 35, x+2 y \leq 50, x \geq 0, y \geq 0\)
  3. C Maximize \(Z=150 x+250 y\),
    Subject to constraints,
    \(x+y \geq 35,2 x+y \leq 50, x \geq 0, y \geq 0\)
  4. D Maximize \(Z=150 x+250 y\),
    Subject to constraints,
    \(x+y \geq 35,2 x+y \geq 50, x \geq 0, y \geq 0\)
Verified Solution

Answer & Solution

Correct Answer

(B) Maximize \(Z=150 x+250 y\),
Subject to constraints,
\(x+y \leq 35, x+2 y \leq 50, x \geq 0, y \geq 0\)

Step-by-step Solution

Detailed explanation

Objective function: Maximize \(Z = 150x + 250y\) Storage constraint: \(x + y \leq 35\) Investment constraint: \(1000x + 2000y \leq 50000 \Rightarrow x + 2y \leq 50\) Non-negativity: \(x \geq 0, y \geq 0\) The correct option is: Maximize \(Z=150 x+250 y\), Subject to constraints,…
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