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CUET · MATHS · PYQ PAPER 2025

A function \(f: R \rightarrow\{x \in R:-1< x<1\}\) is defined as \(f(x)=\frac{x}{1+|x|}\), then \(f\) is :

  1. A neither one-one nor onto
  2. B one-one only
  3. C onto only
  4. D both one-one and onto
Verified Solution

Answer & Solution

Correct Answer

(D) both one-one and onto

Step-by-step Solution

Detailed explanation

For one-one: For \(x>0\), \(f'(x) = \frac{d}{dx}\left(\frac{x}{1+x}\right) = \frac{1}{(1+x)^2} > 0\). For \(x 0\). If \(x_1>0, x_2\(f\) is strictly increasing over its domain \(R\), thus \(f\) is one-one. For onto: Let \(y \in (-1,1)\). We find \(x\) such that \(f(x)=y\). If…