CUET · MATHS · PYQ PAPER 2025
A function \(f: R \rightarrow R\) defined by \(f(x)=\frac{x}{x^2+1}\) is (where \(R\) is the set of real numbers) :
- A one-one but not onto
- B onto but not one-one
- C neither one-one nor onto
- D both one-one and onto
Answer & Solution
Correct Answer
(C) neither one-one nor onto
Step-by-step Solution
Detailed explanation
To check if \(f\) is one-one: \(f(2) = \frac{2}{2^2+1} = \frac{2}{5}\) \(f\left(\frac{1}{2}\right) = \frac{\frac{1}{2}}{\left(\frac{1}{2}\right)^2+1} = \frac{\frac{1}{2}}{\frac{1}{4}+1} = \frac{\frac{1}{2}}{\frac{5}{4}} = \frac{2}{5}\) Since \(f(2) = f\left(\frac{1}{2}\right)\)…
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