CUET · MATHS · PYQ PAPER 2025
A fair coin is tossed a fixed number of times. If the probability of getting 11 heads is equal to the probability of getting 13 heads, then the probability of getting 2 heads is:
- A \(\frac{69}{2^{22}}\)
- B \(\frac{23}{2^{24}}\)
- C \(\frac{69}{2^{24}}\)
- D \(\frac{23}{2^{22}}\)
Answer & Solution
Correct Answer
(A) \(\frac{69}{2^{22}}\)
Step-by-step Solution
Detailed explanation
\(\binom{N}{11} = \binom{N}{13}\) \(N = 11 + 13 = 24\) \(P(X=2) = \frac{\binom{24}{2}}{2^{24}}\) \(P(X=2) = \frac{\frac{24 \times 23}{2 \times 1}}{2^{24}}\) \(P(X=2) = \frac{12 \times 23}{2^{24}} = \frac{276}{2^{24}}\)…
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