CUET · MATHS · PYQ PAPER 2023
A fair coin is tossed 10 times. The probability of obtaining exactly six heads is:
- A \(\frac{105}{512}\)
- B \(\frac{107}{512}\)
- C \(\frac{210}{512}\)
- D \(\frac{53}{64}\)
Answer & Solution
Correct Answer
(A) \(\frac{105}{512}\)
Step-by-step Solution
Detailed explanation
\( P(X=k) = \binom{n}{k} p^k (1-p)^{n-k} \) \( P(X=6) = \binom{10}{6} (0.5)^6 (0.5)^{10-6} \) \( P(X=6) = \frac{10!}{6!4!} \times (0.5)^{10} \) \( P(X=6) = 210 \times \frac{1}{1024} \) \( P(X=6) = \frac{210}{1024} = \frac{105}{512} \)
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