CUET · MATHS · PYQ PAPER 2025
A die is thrown three times. If the first throw is a five, the probability of getting 14 as the sum is:
- A \(\frac{1}{9}\)
- B \(\frac{ 1 }{ 1 8 }\)
- C \(\frac{ 1 }{ 3 6 }\)
- D \(\frac{1}{54}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{9}\)
Step-by-step Solution
Detailed explanation
\(D_1=5 \Rightarrow D_2+D_3 = 14-5 = 9\) Favorable outcomes for \((D_2,D_3)\): \((3,6), (4,5), (5,4), (6,3)\) Number of favorable outcomes = 4 Total possible outcomes for \((D_2,D_3)\) = \(6 \times 6 = 36\) Probability = \(\frac{4}{36} = \frac{1}{9}\)
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