CUET · MATHS · PYQ PAPER 2025
A cylindrical drum of radius 7 cm and height 2 m is being kept in a vertical position filled with milk. If the milk is leaking at \(14 cm^3 / sec\) from its lower base, then the rate of decrease in the level of milk is: [Take \(\pi=\frac{22}{7}\) ]
- A \(\frac{2}{11}\) cm/sec
- B \(\frac{1}{11}\) cm/sec
- C \(\frac{3}{11}\) cm/sec
- D \(\frac{4}{11}\)cm/sec decreases
Answer & Solution
Correct Answer
(B) \(\frac{1}{11}\) cm/sec
Step-by-step Solution
Detailed explanation
\(V = \pi r^2 h\) \(\frac{dV}{dt} = \pi r^2 \frac{dh}{dt}\) \(-14 = \frac{22}{7} \times (7)^2 \times \frac{dh}{dt}\) \(\frac{dh}{dt} = \frac{-14}{\frac{22}{7} \times 49} = \frac{-14}{22 \times 7} = \frac{-14}{154} = -\frac{1}{11}\) Rate of decrease in milk level is…
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