CUET · MATHS · PYQ PAPER 2023
A cone, whose height is always equal to its diameter, is increasing in volume at the rate of \(40 cm^3 / sec\). The rate at which radius is increasing when circular base area is \(1 m^2\) is :
- A 1 mm/sec
- B 2 mm/sec
- C 0.01 mm/sec
- D 0.002 mm/sec
Answer & Solution
Correct Answer
(D) 0.002 mm/sec
Step-by-step Solution
Detailed explanation
\(h = 2r\) \(V = \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi r^2 (2r) = \frac{2}{3}\pi r^3\) \(\frac{dV}{dt} = 2\pi r^2 \frac{dr}{dt}\) \(A = \pi r^2 = 1 m^2 = 10000 cm^2\) \(40 cm^3/sec = 2 (10000 cm^2) \frac{dr}{dt}\)…
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