CUET · MATHS · PYQ PAPER 2025
A box contains 10 balls, each marked with one of the digits 0 to 9 .
If four balls are drawn successively with replacement from the box,
then the probability that none is marked with the digit \(0\) is :
- A \(\left(\frac{9}{10}\right)^4\)
- B \(\left(\frac{1}{10}\right)\left(\frac{9}{10}\right)^3\)
- C \(\left(\frac{1}{10}\right)^4\)
- D \(\left(\frac{1}{10}\right)^2\left(\frac{9}{10}\right)^2\)
Answer & Solution
Correct Answer
(A) \(\left(\frac{9}{10}\right)^4\)
Step-by-step Solution
Detailed explanation
Probability of not drawing \(0\) in one draw \( = \frac{\text{Number of outcomes without } 0}{\text{Total number of outcomes}} = \frac{9}{10} \). Probability of not drawing \(0\) in four successive draws with replacement \( = \left(\frac{9}{10}\right)^4 \).
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