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CUET · MATHS · PYQ PAPER 2025

A bag contains 8 blue and 12 green balls. Two balls are drawn in succession without replacement.
The probability that first is blue and second is green is

  1. A \(\frac{42}{95}\)
  2. B \(\frac{71}{95}\)
  3. C \(\frac{8}{25}\)
  4. D \(\frac{24}{95}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{42}{95}\)

Step-by-step Solution

Detailed explanation

\(P(\text{first is blue}) = \frac{8}{20}\) \(P(\text{second is green}|\text{first is blue}) = \frac{12}{19}\) \(P(\text{first is blue and second is green}) = \frac{8}{20} \times \frac{12}{19} = \frac{2}{5} \times \frac{12}{19} = \frac{24}{95}\)
From CUET
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