CUET · MATHS · PYQ PAPER 2025
A bag contains 8 blue and 12 green balls. Two balls are drawn in succession without replacement.
The probability that first is blue and second is green is
- A \(\frac{42}{95}\)
- B \(\frac{71}{95}\)
- C \(\frac{8}{25}\)
- D \(\frac{24}{95}\)
Answer & Solution
Correct Answer
(A) \(\frac{42}{95}\)
Step-by-step Solution
Detailed explanation
\(P(\text{first is blue}) = \frac{8}{20}\) \(P(\text{second is green}|\text{first is blue}) = \frac{12}{19}\) \(P(\text{first is blue and second is green}) = \frac{8}{20} \times \frac{12}{19} = \frac{2}{5} \times \frac{12}{19} = \frac{24}{95}\)
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