CUET · MATHS · PYQ PAPER 2025
A bag contains 4 red and 6 green balls. A ball is drawn at random, its colour is noted and is returned to the bag.
One additional ball of the colour drawn is put in the bag. Again a ball is then drawn from the bag. The probability of this ball to be of green colour is
- A \(\frac{7}{10}\)
- B \(\frac{4}{5}\)
- C \(\frac{3}{5}\)
- D \(\frac{2}{5}\)
Answer & Solution
Correct Answer
(C) \(\frac{3}{5}\)
Step-by-step Solution
Detailed explanation
\(P(G_2) = P(R_1)P(G_2|R_1) + P(G_1)P(G_2|G_1)\) \(P(G_2) = \left(\frac{4}{10} \cdot \frac{6}{11}\right) + \left(\frac{6}{10} \cdot \frac{7}{11}\right)\) \(P(G_2) = \frac{24}{110} + \frac{42}{110}\) \(P(G_2) = \frac{66}{110}\) \(P(G_2) = \frac{3}{5}\)
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