CUET · MATHS · PYQ PAPER 2025
A \(95 \%\) confidence interval for a population mean was reported to be 152 to 160 , if sample standard deviation \(\sigma=15\), then sample size used in this study is (Given \(Z_{0.025}=1.96\) )
- A 60
- B 50
- C 52
- D 54
Answer & Solution
Correct Answer
(D) 54
Step-by-step Solution
Detailed explanation
\( ME = \frac{160 - 152}{2} = 4 \) \( n = \left( \frac{Z \sigma}{ME} \right)^2 = \left( \frac{1.96 \times 15}{4} \right)^2 \) \( n = (7.35)^2 = 54.0225 \approx 54 \)
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