CUET · MATHS · PYQ PAPER 2023
\(\int \sin^3 x dx\) is equal to:
- A \(\frac{\cos^3 x}{3} + \cos x + C\)
- B \(\frac{\cos^3 x}{3} - \cos x + C\)
- C \(\frac{\cos^2 x}{3} - \cos x + C\)
- D \(\frac{\sin^3 x}{3} + \sin x + C\)
Answer & Solution
Correct Answer
(B) \(\frac{\cos^3 x}{3} - \cos x + C\)
Step-by-step Solution
Detailed explanation
\(\int \sin^3 x dx = \int (1 - \cos^2 x) \sin x dx\) Let \(u = \cos x \Rightarrow du = -\sin x dx\) \(= \int (1 - u^2) (-du) = \int (u^2 - 1) du\) \(= \frac{u^3}{3} - u + C\) \(= \frac{\cos^3 x}{3} - \cos x + C\)
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