CUET · MATHS · PYQ PAPER 2023
\(\int \frac{1}{x \sqrt{x^2-9}} d x\) is equal to (given that C is constant of integration)
- A \(\sec ^{-1} \frac{x}{3}+C\)
- B \(\frac{1}{3} \sec ^{-1} \frac{x}{3}+C\)
- C \(3 \sec ^{-1} x+C\)
- D \(\operatorname{cosec}^{-1} x+C\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{3} \sec ^{-1} \frac{x}{3}+C\)
Step-by-step Solution
Detailed explanation
\( \int \frac{1}{x \sqrt{x^2-a^2}} d x = \frac{1}{a} \sec^{-1} \left(\frac{x}{a}\right) + C \) \( a=3 \) \( \frac{1}{3} \sec^{-1} \left(\frac{x}{3}\right) + C \)
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