CUET · MATHS · PYQ PAPER 2023
\(\int \frac{1 - \sin x}{\cos^2 x} dx\) is equal to:
- A \(\tan x - \sec x + C\) where C is the constant of integration
- B \(\cot x-\backslash \operatorname{cosec} x+C\) where C is the constant of integration
- C \(\tan x + \sec x + C\) where C is the constant of integration
- D \(\cot x+\backslash \operatorname{cosec} x+C\) where C is the constant of integration
Answer & Solution
Correct Answer
(A) \(\tan x - \sec x + C\) where C is the constant of integration
Step-by-step Solution
Detailed explanation
\(\int \left( \frac{1}{\cos^2 x} - \frac{\sin x}{\cos^2 x} \right) dx\) \(\int \left( \sec^2 x - \tan x \sec x \right) dx\) \(\tan x - \sec x + C\)
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