CUET · MATHS · PYQ PAPER 2025
\(\int \frac{1}{(x+1)(x+2)} d x\) is equal to
- A \(\log _e\left|\frac{x+2}{x+1}\right|+C\)
- B \(\log _e\left|\frac{x+1}{x+2}\right|+C\)
- C \(\log _e|(x+1)(x+2)|+C\)
- D \(\log _e|2 x+3|+C\)
Answer & Solution
Correct Answer
(B) \(\log _e\left|\frac{x+1}{x+2}\right|+C\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{(x+1)(x+2)} = \frac{1}{x+1} - \frac{1}{x+2}\) \(\int \left(\frac{1}{x+1} - \frac{1}{x+2}\right) d x = \log _e|x+1| - \log _e|x+2| + C\) \(= \log _e\left|\frac{x+1}{x+2}\right|+C\)
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