CUET · MATHS · PYQ PAPER 2025
\(\int_1^2 \frac{1}{x(x+1)} d x, x>0\) equals
- A \(\log \left(\frac{2}{3}\right)\)
- B \(\log \left(\frac{4}{3}\right)\)
- C 0
- D \(\log \left(\frac{3}{4}\right)\)
Answer & Solution
Correct Answer
(B) \(\log \left(\frac{4}{3}\right)\)
Step-by-step Solution
Detailed explanation
\(\int_1^2 \left(\frac{1}{x} - \frac{1}{x+1}\right) d x\) \(\left[\log|x| - \log|x+1|\right]_1^2\) \(\left[\log\left(\frac{x}{x+1}\right)\right]_1^2\) \(\log\left(\frac{2}{2+1}\right) - \log\left(\frac{1}{1+1}\right)\)…
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