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CUET · MATHS · PYQ PAPER 2025

\(\int_{-1}^1 \frac{x^3+|x|+1}{x^2+2|x|+1} d x\) is equal to

  1. A \(\frac{1}{2} \log _e 2-1\)
  2. B \(2 \log _e 2\)
  3. C \(2 \log _e 2-2\)
  4. D \(4 \log _e 2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2 \log _e 2\)

Step-by-step Solution

Detailed explanation

\( \int_{-1}^1 \frac{x^3+|x|+1}{x^2+2|x|+1} d x = \int_{-1}^1 \left( \frac{x^3}{(|x|+1)^2} + \frac{|x|+1}{(|x|+1)^2} \right) d x \) \( = \int_{-1}^1 \frac{x^3}{(|x|+1)^2} d x + \int_{-1}^1 \frac{1}{|x|+1} d x \) \( = 0 + 2 \int_0^1 \frac{1}{x+1} d x \)…
From CUET
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