CUET · MATHS · PYQ PAPER 2023
\(\int_0^2 \frac{\sqrt{x}}{\sqrt{x}+\sqrt{2-x}} d x\) is equal to:
- A \(0\)
- B 2
- C \(\frac{3}{2}\)
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
\(I = \int_0^2 \frac{\sqrt{x}}{\sqrt{x}+\sqrt{2-x}} d x\) \(I = \int_0^2 \frac{\sqrt{2-x}}{\sqrt{2-x}+\sqrt{x}} d x\) (using \(\int_a^b f(x) dx = \int_a^b f(a+b-x) dx\))…
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