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CUET · MATHS · PYQ PAPER 2023

\(\int_0^2 \frac{\sqrt{x}}{\sqrt{x}+\sqrt{2-x}} d x\) is equal to:

  1. A \(0\)
  2. B 2
  3. C \(\frac{3}{2}\)
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(D) 1

Step-by-step Solution

Detailed explanation

\(I = \int_0^2 \frac{\sqrt{x}}{\sqrt{x}+\sqrt{2-x}} d x\) \(I = \int_0^2 \frac{\sqrt{2-x}}{\sqrt{2-x}+\sqrt{x}} d x\) (using \(\int_a^b f(x) dx = \int_a^b f(a+b-x) dx\))…