CUET · MATHS · PYQ PAPER 2025
\(\int_0^2(|x|+|x-2|) d x=\)
- A 8
- B 4
- C 2
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
For \( x \in [0,2] \), \( |x|=x \) and \( |x-2|=2-x \). \( \int_0^2 (x + 2 - x) dx = \int_0^2 2 dx = [2x]_0^2 = 2(2) - 2(0) = 4 \).
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