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CUET · MATHS · PYQ PAPER 2023

\(\int_0^2|x-1| d x=\)

  1. A 1
  2. B 2
  3. C 3
  4. D \(\frac{3}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) 1

Step-by-step Solution

Detailed explanation

\(\int_0^2|x-1| d x = \int_0^1(1-x) d x + \int_1^2(x-1) d x\) \(= \left[x - \frac{x^2}{2}\right]_0^1 + \left[\frac{x^2}{2} - x\right]_1^2\) \(= \left(1 - \frac{1}{2}\right) - (0) + \left(\frac{4}{2} - 2\right) - \left(\frac{1}{2} - 1\right)\)…
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