\(Zn (s) \rightarrow Zn^{2+} + 2e^-\text{}\)
Above reaction at anode is found in:

What types of bond (linkage) are present in nucleotide?

The increasing order of osmotic pressure of 0.1 M aqueous solution of the following is:
(A) \(MgCl _2\)
(B) NaCl
(C) \(NH _2 CONH _2\)
(D) \(K _3\left[ Fe ( CN )_6\right]\)
Choose the correct answer from the options given below:

When \(CuSO_4\) solution is electrolysed using platinum electrodes, which of the following is true ?

Read the passage given below and answer the question.
The transition elements which give the greatest number of oxidation states occur in or near the middle of the series. Manganese, for example, exhibits all the oxidation states from +2 to +7 . The lesser number of oxidation states at extreme ends stems from either too few electrons to lose or share (Sc, Ti) on too many d-electrons (hence fewer orbitals available in which to share electrons with others) for higher valence \(( Cu , Zn )\). Thus early in the series scandium (II) is virtually unknown and titanium (IV) is more stable than Ti (III) or Ti (II). At the other end, the only oxidation state of zinc is \(+ 2\) (no d electrons are involved). The maximum oxidation states of reasonable stability correspond in value to the sum of the s - and d-electrons upto manganese ( \(Ti ^{I V} O _2, V^V O _2^{+}, Cr ^{V I} O _4^{2-}\), \(Mn ^{\text {VII }} O _4\) ) followed by a rather abrupt decrease in stability of higher oxidation states, so that the typical species to follow are \(Fe ^{I I, I I I}, Co ^{I I, I I I}, Ni ^{I I}, Cu ^{I, I I}, Zn ^{I I}\).
The variability of oxidation states, a characteristic of transition elements, arises out of incomplete filling of d-orbitals in such a way that their oxidation states differ from each other by unity, e.g. \(V ^{I I}, V^{I I I}, V^{I V}, V^V\). This is in contrast with the variability of oxidation states of non transition elements where oxidation states normally differ by a unit of two.
An interesting feature in the variability of oxidation states of the d-block elements is noticed among the groups (groups 4 through 10). Although in the p-block, the lower oxidation states are favoured by the heavier members (due to inert pair effect), the opposite is true in the groups of dblock. For example, in group 6, \(Mo ( VI )\) and \(W ( VI )\) are found to be more stable than \(Cr ( VI )\). The \(Cr ( VI )\) in the form of dichromate in acidic medium is a strong oxidising agent, whereas \(MoO _3\) and \(WO _3\) are not.
Low oxidation states are found when a complex compound has ligands capable of \(\pi\)-acceptor character in addition to the \(\sigma\)-bonding. For example, in \(Ni ( CO )_4\) and \(Fe ( CO )_5\), the oxidation state of nickel and iron is zero.
Most acidic species among the following is :

Answer the question on basis of passage given below :
P block elements are placed in groups 13 to 18 of the periodic table. Their valence shell electronic configuration is \(ns^2 np^{1-6}\). Group 16 of the p block elements are known as the group of chalcogens having \(ns^2 np^4\) as their general electronic configuration. They exhibit number of oxidation states but the stability of \(- 2\) oxidation state decreases down the group. They are sometimes also known as group of chalcogens as the name is derived from the Greek word for brass and points to the association of sulphur and its congeners with copper. Their ionisation enthalpy decreases down the group. Oxygen shows anomalous behaviour due to its small size and high electronegativity.
Which one is the correct electronic configuration of sulphur?

Match the complex species given in List-l with the possible isomerism given in List-ll:

List-l Complex species	List-ll Isomerism
(A) \(\left[ Co \left( NH _3\right)_4 Cl _2\right]^{+}\)	(I) optical
(B) cis- \(\left[ Co ( en )_2 Cl _2\right]^{+}\)	(II) ionization
(C) \(\left[ Co \left( NH _3\right)_5\left( NO _2\right)\right] Cl _2\)	(III) coordination
(D) \(\left[ Co \left( NH _3\right)_6\right]\left[ Cr ( CN )_6\right]\)	(IV) geometrical

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Read the passage carefully and answer the Questions
Haloalkanes undergo nucelophilic substitution reactions owing to the polarity of CX bond. The nucleophile reacts with the haloalkane on the carbon possessing a partial positive charge holding the halogen atom. The halogen atom X is replaced by a nucleophile. Depending on the kinetics and mode of bond breaking, the mechanism can be either SN1 or SN2 reaction. The rate of SN1 reaction is governed by the stability of carbocation and in SN2 reaction, the rate of reaction is governed by steric factor. Chirality is the main factor in both SN1and SN2. In SN1 reaction, the chirality of alkyl halide is accompanied by racemization of the product, while in SN2 reaction, the product is characterized by inversion of configuration. The structure of alkyl halide and the nature of the solvent also governs the mechanism of the substitution.
Hydrolysis of 2-Chlorobutane will result in formation of

If \(f(x)=\frac{1}{2 x+1}, x \neq-\frac{1}{2}\), then \(f[f(x)]\) is :

Identify the carbohydrate which is not a polysaccharide

Which of the following compounds will not undergo azo coupling reaction with benzene diazonium chloride?

Some heat is developed in a uniform metallic wire across the ends of which a constant voltage V is applied. The heat developed will be tripled if

Select the statements which do not hold true for Cancer:
A. Cancerous cells show a property of contact inhibition.
B. Metastasis is the most feared property of malignant tumors.
C. Malignant tumor cells invade and damage the surrounding tissue.
D. Malignant tumor cells grows slowly
Choose the correct answer from the options given below: