Which one of the following will exhibit maximum paramagnetic character?

Match List-I and List-II

List-I	List-II
A. Tranquilizers	I. Ofloxacin
B. Antibiotics	II. Chlorodiazepoxide
C. Antacids	III. Seldane
D. Antihistamines	IV. Cimetidine

Choose the correct answer from the options given below:

Read the passage given below and answer the question.
The transition elements which give the greatest number of oxidation states occur in or near the middle of the series. Manganese, for example, exhibits all the oxidation states from +2 to +7. The lesser number of oxidation states at extreme ends stems from either too few electrons to lose or share (Sc, Ti) on too many d-electrons (hence fewer orbitals available in which to share electrons with others) for higher valence (Cu, Zn). Thus early in the series scandium (II) is virtually unknown and titanium (IV) is more stable than Ti (III) or Ti (II). At the other end, the only oxidation state of zinc is +2 (no d electrons are involved). The maximum oxidation states of reasonable stability correspond in value to the sum of the s- and d-electrons upto manganese (\(TiO_2, VVO^+, CrVIO_4^{2-}, MnVIIO_4\)) followed by a rather abrupt decrease in stability of higher oxidation states, so that the typical species to follow are \(Fe^{II,III}, Co^{II,III}, Ni^{II}, Cu^{I,II}, Zn^{II}\).
The variability of oxidation states, a characteristic of transition elements, arises out of incomplete filling of d-orbitaIs in such a way that their oxidation states differ from each other by unity, e.g. \(V ^{I I}, V^{I I I}, V^{I V}, V^V\). This is in contrast with the variability of oxidation states of non transition elements where oxidation states normally differ by a unit of two.
An interesting feature in the variability of oxidation states of the d-block elements is noticed among the groups (groups 4 through 10). Although in the p-block, the lower oxidation states are favoured by the heavier members (due to inert pair effect), the opposite is true in the groups of dblock. For example, in group 6, Mo(VI) and W(VI) are found to be more stable than \(Cr ( VI )\). The \(Cr ( VI )\) in the form of dichromate in acidic medium is a strong oxidising agent, whereas \(MoO _3\) and \(WO _3\) are not.
Low oxidation states are found when a complex compound has ligands capable of \(\pi\)-acceptor character in addition to the \(\sigma\)-bonding. For example, in \(Ni ( CO )_4\) and \(Fe ( CO )_5\), the oxidation state of nickel and iron is zero.
Highest oxidation state shown by 'Mn' is :

Match List-I With List-II

LIST – I (Transition metal ion)	LIST – II (Property)
(A) \(Mn ^{3+}\)	(I) \(3 d^6\), green
(B) \(Fe ^{2+}\)	(II) \(3 d^4\), violet
(C) \(Ti ^{4+}\)	(III) \(3 d^0\), colourless
(D) \(V ^{2+}\)	(IV) \(3 d^3\), violet

Choose the correct answer from the options below:

Which of the following compounds can be prepared by Sandmeyer's reaction?
(A) Chlorobenzene
(B) Bromobenzene
(C) Cyanobenzene
(D) Fluorobenzene
Choose the correct answer from the options given below:

Given below are reduction potentials :
(A) \(E _{ Cu ^{2+} / Cu }^0=0.34 V\)
(B) \(E _{ Sn ^{2+} / Sn }^0=-0.14 V\)
(C) \(E _{ Zn ^{2+} / Zn }^0=-0.76 V\)
(D) \(E _{ K ^{+} / K }^0=-2.93 V\)
The strongest reducing agent from the above is :

The decreasing order of reducing power of the given species as per their standard reduction potentials is :
A. \(- 2.36\)
B. \(+0.54\)
C. \(+1.23\)
D. \(-0.74\)
E. \(+ 1.81\)
Choose the correct answer from the options given below :

Sickle cell anaemia is :

The rate of change of volume of a sphere with respect to its surface area, when radius is 4 cm, is equal to

If \(3\left[\begin{array}{cc}x & y \\ z & w\end{array}\right]=\left[\begin{array}{cc}x & 6 \\ -1 & 2 w\end{array}\right]+\left[\begin{array}{cc}4 & x+y \\ z+w & 3\end{array}\right]\), then the values of \(x, y, z\) and \(w\) are

The constraints of the given shaded feasible region below of an L.P.P., for non-negative variable constraints \(x\) and \(y\) are

The maximum value of \((\sin x)(\cos x)\) is :

The karyotype in klinefelter's syndrome is: