Which of the following can be used as a froth stabiliser during ore concentration?

In the electrolytic refining of silver :

The vapour pressures of chloroform, (\(\text{CHCl}_3\)) and dichloromethane (\(\text{CH}_2\text{Cl}_2\)) at 298 K are 400 mm Hg and 615 mm Hg,respectively. What is the mole fraction of \(\text{CHCl}_3\) in vapour phase in solution prepared by mixing 30 g of \(\text{CHCl}_3\) and 45 g of \(\text{CH}_2\text{Cl}_2\) ?

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The degeneracy of the \(d\) orbitals has been removed due to ligand electron-metal electron repulsions in the octahedral comples to yield three orbitals of lower energy, \(t_{2 g}\) set and two orbitals of higher energy, \(e_g\) set. This splitting of the degenerate levels due to the presence of ligands in a definite geometry is termed as crystal field splitting and the energy separation is denoted by \(\Delta_0\). Thus energy of the two \(e_g\) orbitals will increase by \((3 / 5) \Delta_0\) and that of three \(t_{2 g}\) will decrease by \((2 / 5) \Delta_0\). The crystal field splitting \(\Delta_0\) depends upon the field produced by the ligand and charge on the metal ion. Some ligands are able to produce strong fields, in which case the splitting will be large, whereas others produce weak fields and consequently result in small splitting of \(d\) orbitals. Relative magnitude of crystal field splitting energy \(\Delta_{\circ}\) and pairing energy, \(P\) (energy required for electron pairing in a single orbital) determine the formation of low spin ( \(\Delta_0>P\) ) or high spin ( \(\Delta_0<P\) ) complex. In tetrahedral coordination entity formation, the \(d\)-orbital splitting is inverted and is smaller as compared to the octahedral field splitting. The crystal field theory attributes the colour of the complex to \(d-d\) transition of the electron. The colour of the coordination compounds depends on the crystal field splitting. In the absence of ligand, crystal field splitting does not occur and hence the substance is colourless.
Choose the correct order of the ligands in their increasing crystal field splitting:

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Carboxylic acids are the organic compounds which comprise of carboxyl functional group, -COOH. These are generally found in nature, some higher members are known as fatty acids as they occur in natural fats as esters of glycerol. They can be prepared from oxidation of alcohols and aldehydes, hydrolysis of nitriles and amides and Grignard reagents. They are stronger acids than simple phenols and alcohols. but weaker than mineral acids. Substituents affect the acidity of aliphatic and aromatic carboxylic acids. They undergo reactions involving cleavage of -OH and C-OH bond. Carboxylic acids having an alpha hydrogen get halogenated in the presence of red phosphorus to form alpha halo carboxylic acids. The reaction is known as Hell Volhard Zelinsky reaction. Besides these aromatic carboxylic acids undergo electrophilic substitution reactions. They are versatile and are employed in the manufacture of various useful compounds. For example, methanoic acid is used in rubber, textile, dyeing, leather and electroplating industries. Higher fatty acids are used in the manufacture of soaps and detergents. Esters of Benzoic acid are used in perfumery.
Esterification of carboxylic acid with alcohols or phenols is which type of reaction?

List-I (Reaction Name)	List-II (Reaction)
(A) Carbylamine reaction	(I)
(B) Gatterman Rection	(II)
(C) Sandmeyer reaction	(III)
(D) Hoffmann Bromamide reaction	(IV)

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A compound is formed by two elements X and Y.
Atoms of 'Y' make ccp and those of element 'X' occupy tetrahedral voids.
The formula of the compound is:

Match List - I and List - II

LIST – I (Name of vitamins)	LIST – II (Deficiency Disesse)
(A) Vitamin - A	(I) Increase in fragility of RBC
(B) Vitamin - E	(II) Increased blood clotting time
(C) Vitamin - C	(III) Xerophthalmia
(D) Vitamin - K	(IV) Scurvy

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Prehistoric cave art developed about 18000 years ago. Such cave paintings by prehistoric humans can be seen in India at :

A cone, whose height is always equal to its diameter, is increasing in volume at the rate of \(40 cm^3 / sec\). The rate at which radius is increasing when circular base area is \(1 m^2\) is :

The speed of an electromagnetic wave in a medium of dielectric constant 2.25 and relative permeability 4 is:

Match List-I with List-II

List-I	List-II
(A) Catalysts alter the rate of reaction	(I) cannot be fraction or zero
(B) Molecularity	(II) by lowering the activation energy
(C) Second half life of a first order reaction	(III) is the same as the first
(D) \(e^{-E_a / R T}\)	(IV) refers to the fraction of molecules with energy equal to or greater than activation energy

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Current is a__________ quantity and it's SI unit is__________.