When phenol is treated with bromine water, the product formed is :

Match List-l with List-ll

List-l (Electronic configuration)	List-II (lon)
(A) \([ Ar ] 3 d^{10}\)	(I) \(Ce ^{4+}\)
(B) \(\left[ X _{ e }\right]\)	(II) \(Cu ^{+}\)
(C) \([ Rn ]\)	(III) \(Th ^{4+}\)
(D) \([ Xe ] 4 f^{11} 5 d^1\)	(IV) \(Lu ^{2+}\)

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Read the passage carefully and answer the questions
The resistance ( \(R\) ) of an object is given by the expression \(R=\rho \frac{l}{A}\)
The inverse of \(R\) is called conductance and the inverse of \(\rho\) is called conductivity or specific conductance represented by \(\kappa\).
The conductivity depends upon the nature of the material (insulator, semiconductor or conductor) and the temperature of the substance.
Similarly, the conductance due to the ions present in the solution. (ionic conductance) depends upon the nature of the electrolyte, size of ions, the nature of the solvent and the temperature.
Molar conductivity ( \(\Lambda _{ m }\) ) of a solution at a given concentration is the conductance of volume \(V\) containing one mole of electrolyte kept between two electrodes of area \(A\) and unit distance apart.
It is given by the expression.\(A_m=\kappa V .\)
Molar conductivity increases with decrease in concentration and when concentration approaches sero, it is called limiting molar conductivity.
The decrease is linear for a strong electrolyte. However, for a weak electrolyte the change is gradual at higher concentrations and sharp near zero concentration.
Using limiting molar conductivity values of strong electrolytes we can calculate the limiting molar conductivity of weak electrolytes using Kohlrausch law of independent migration of ions.
From molar conductivity and limiting molar conductivity we can determine the degree of dissociation \(\left(\frac{\Lambda_m}{\Lambda_m^0}\right)\) and the ionisation constant of a weak acid.
The limiting molar conductivity values for \(HCl , NaCl\) and \(CH _3 COONa\) are \(425.9,126.4\) and \(91.0 S cm ^2 mol^{-1}\), respectively.
Calculate the limiting molar conductivity value for acetic acid.

The role of cryolite in the metallurgy of aluminum is:-

Read the passage carefully and answer the questions
Sodium dichromate \(Na _2 Cr _2 O _7\) and Potassium dichromate \(K _2 Cr _2 O _7\) are strong oxidizing agents; in acidic solution, its oxidising action can be represented as follows :
\(Cr _2 O _7^{2-}+14 H ^{+}+6 e^{-} \rightarrow 2 Cr ^{3+}+7 H _2 O \left( E ^{\circ}=1.33 V\right)\)
The chromates and dichromates are interconvertible in aqueous solution depending upon pH of the solution.
The chromate ion is tetrahedral whereas the dichromate ion consists of two tetrahedra sharing one corner with \(Cr - O - Cr\) bond angle of \(126^{\circ}\)
Potassium permanganate is prepared by fusion of \(MnO _2\) with an alkali metal hydroxide and an oxidising agent like \(KNO _3\).
This produces the dark green \(K _2 MnO _4\) which disproportionates in a neutral or acidic solution to give permanganate. It is a strong oxidizing agent. Hydrogen ion concentration of the solution plays 
an important part in the reduction of permanganate to manganate, manganese dioxide and manganese(II) salt.
Potassium permanganate forms dark purple (almost black) crystals which are isostructural with those of \(KClO _4\).
The salt is not very soluble in water \((6.4 g / 100 g\) of water at 293 K ), but when heated it decomposes at 513 K.
The number of moles of KMnO₄ required to react with one mole of sulphide ion in acidic solution is

Match List-l with List-II

List-l (Test)	List-II (Identification)
(A) Hinsberg's Test	(I) Primary, Secondary and tertiary Amines
(B) Isocyanide test	(II) Aliphatic and Aromatic primary amines
(C) Azo dye test	(III) Primary Aromatic amines
(D) Tollen's Test	(IV) Reducing sugars

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Since Physisorption arises mainly because of van der Waals forces, it means adsorption is:
(pick the incorrect option)

Which of the following sols are correctly matched with their corresponding charges ?
(A) \(\text{Cr(OH)}_3\) sol : negatively charged sol
(B) \(\text{TiO}_2\) sol : positively charged sol
(C) \(\text{CdS}\) sol: positively charged sol
(D) Gum: negatively charged sol
(E) Silver sol : positively charged sol
Choose the correct answer from the options given below :

The magnetic behaviour of manganate ion and permanganate ions, respectively, are

Two electric bulbs of 60 W and 100 W powers, respectively are connected in series across a 220 V supply. The current is :

The unit's digit of \(2^{2025}\) is

An electron of mass \( 9.11 \times 10^{-31} \text{ kg} \) is moving with velocity \( 5.4 \times 10^6 \text{ m/s} \). Its momentum will be

Match List-I with List-II

List-I (Optical instrument)	List-II (Magnifying power)
(A) Magnifying power m of a simple microscope	(I) \( m = 1 + (D/f) \)
(B) Magnifying power m of a simple microscope if the image is at infinity	(II) \( m = (L/f_0) \times (D/f_e) \)
(C) Magnifying power m of a compound microscope	(III) \( m = f_0 / f_e \)
(D) Magnifying power m of a telescope	(IV) \( m = D/f \)

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