CUET · CHEMISTRY · PYQ PAPER 2025
When 1 mol of CrCl\(_3\) \(\cdot\) 6H\(_2\)\(O\) is treated with excess AgNO\(_3\), 3 mol of AgCl are obtained.
The conductivity of the solution will correspond to:
- A 1:1 electrolyte
- B 1:2 electrolyte
- C 2:1 electrolyte
- D 1:3 electrolyte
Answer & Solution
Correct Answer
(D) 1:3 electrolyte
Step-by-step Solution
Detailed explanation
\( \text{CrCl}_3 \cdot 6\text{H}_2\text{O} \) reacts with excess \( \text{AgNO}_3 \) to yield \( 3 \text{ mol} \) of \( \text{AgCl} \). This implies that all three chloride ions are outside the coordination sphere, so the complex is \( \text{[Cr(H}_2\text{O)}_6\text{]Cl}_3 \).…
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