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CUET · CHEMISTRY · PYQ PAPER 2023

What is the maximum molarity of \(MgCl_2\) in aqueous solution,
if its solubility product is \(4 \times 10^{-28}\)? 

  1. A 1.6 \(\times 10^{-9}\) mol L-1
  2. B 1.3 \(\times 10^{-14}\) mol L-1
  3. C \(\sqrt[3]{10} \times 10^{-9} mol L ^{-1}\)
  4. D \(\sqrt{10} \times 10^{-14}\) mol L-1
Verified Solution

Answer & Solution

Correct Answer

(C) \(\sqrt[3]{10} \times 10^{-9} mol L ^{-1}\)

Step-by-step Solution

Detailed explanation

\(MgCl_2(s) \rightleftharpoons Mg^{2+}(aq) + 2Cl^-(aq)\) \(K_{sp} = [Mg^{2+}][Cl^-]^2 = (s)(2s)^2 = 4s^3\) \(4s^3 = 4 \times 10^{-28}\) \(s^3 = 10^{-28}\) \(s = (10 \times 10^{-27})^{1/3}\) \(s = \sqrt[3]{10} \times 10^{-9}\) mol L-1
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