CUET · CHEMISTRY · PYQ PAPER 2025
What are the products of the following reaction in neutral solution?
\(\mathrm{MnO}_4^{-}+\mathrm{S}_2 \mathrm{O}_3^{2-}+\mathrm{H}_2 \mathrm{O} \rightarrow ?\)
- A \(\mathrm{MnO}_2, \mathrm{SO}_3^{2-}, \mathrm{H}^{+}\)
- B \(\mathrm{MnO}_2, \mathrm{SO}_2, \mathrm{HO}^{-}\)
- C \(\mathrm{MnO}_2, \mathrm{SO}_4^{2-}, \mathrm{HO}^{-}\)
- D \(\mathrm{Mn}^{2+}, \mathrm{SO}_4^{2-}, \mathrm{H}^{+}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{MnO}_2, \mathrm{SO}_4^{2-}, \mathrm{HO}^{-}\)
Step-by-step Solution
Detailed explanation
\( \mathrm{MnO}_4^{-} \) reduces to \( \mathrm{MnO}_2 \) in neutral solution. \( \mathrm{S}_2 \mathrm{O}_3^{2-} \) oxidizes to \( \mathrm{SO}_4^{2-} \). The products are \( \mathrm{MnO}_2, \mathrm{SO}_4^{2-}, \mathrm{HO}^{-} \).
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