CUET · CHEMISTRY · PYQ PAPER 2023
Total number of isomers for the complex \([\text{FeCl}_2 (\text{C}_2\text{O}_4)_2]^{4-}\) is:
- A 2
- B 3
- C 4
- D 5
Answer & Solution
Correct Answer
(B) 3
Step-by-step Solution
Detailed explanation
Complex type: \([\text{MA}_2\text{B}_2]\) (A = monodentate, B = bidentate oxalate) Trans isomer: 1 (achiral) Cis isomer: 2 (chiral enantiomers) Total isomers = \(1 + 2 = 3\)
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