CUET · CHEMISTRY · PYQ PAPER 2023
To prepare 250 mL standard solution of M/20 \(\text{NaCl}\), amount of \(\text{NaCl}\) required is :
- A 7.3 g
- B 0.73 g
- C 0.073 g
- D 73 g
Answer & Solution
Correct Answer
(B) 0.73 g
Step-by-step Solution
Detailed explanation
\( \text{Molar Mass}(\text{NaCl}) = 22.99 + 35.45 = 58.44 \text{ g/mol} \) \( \text{Mass} = \text{Molarity} \times \text{Volume} \times \text{Molar Mass} \) \( \text{Mass} = \frac{1}{20} \text{ mol/L} \times 0.250 \text{ L} \times 58.44 \text{ g/mol} \)…
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