CUET · CHEMISTRY · PYQ PAPER 2023
The vapour pressure of an aqueous solution of a non-volatile solute which boils at \(101.56^\circ C\) at \(25^\circ C\) will be (V.P. of pure water at \(25^\circ C\) is \(200\ mmHg\) and \(K_b\) for water is \(0.52\ K\ kg\ mol^{-1}\)):
- A 198.98 mmHg
- B 189.8 mmHg
- C 179.6 mmHg
- D 184.7 mmHg
Answer & Solution
Correct Answer
(B) 189.8 mmHg
Step-by-step Solution
Detailed explanation
\(\Delta T_b = 101.56^\circ C - 100^\circ C = 1.56^\circ C\) \(m = \frac{\Delta T_b}{K_b} = \frac{1.56}{0.52} = 3 \ mol \ kg^{-1}\) \(n_{water} = \frac{1000 \ g}{18 \ g \ mol^{-1}} = 55.56 \ mol\)…
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