CUET · CHEMISTRY · PYQ PAPER 2023
The vapour pressure of a solution is 2985 \(\text{Nm}^{-2}\) when 5 g of a non-electrolyte is added to 100 g of water at a particular temperature.
The vapour pressure of pure water at this temperature is 3000 \(\text{Nm}^{-2}\).
The molecular mass of the solute is
- A 179
- B 90
- C 270
- D 200
Answer & Solution
Correct Answer
(A) 179
Step-by-step Solution
Detailed explanation
\(\frac{P_A^0 - P_s}{P_s} = \frac{w_B/M_B}{w_A/M_A}\) \(\frac{3000 - 2985}{2985} = \frac{5/M_B}{100/18}\) \(\frac{15}{2985} = \frac{90}{100 M_B}\) \(M_B = \frac{90 \times 2985}{15 \times 100}\) \(M_B = \frac{90 \times 199}{100} = 179.1\) \(M_B \approx 179\)
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