CUET · CHEMISTRY · PYQ PAPER 2023
The spin-only magnetic moment of \(\left[ MBr _4\right]^{2-}\) is 5.9 BM.
The metal M is:
- A Fe
- B Cr
- C Mn
- D Co
Answer & Solution
Correct Answer
(C) Mn
Step-by-step Solution
Detailed explanation
\(\mu_{spin} = \sqrt{n(n+2)}\) \(5.9 = \sqrt{n(n+2)} \implies n=5\) Oxidation state of M: \(x + 4(-1) = -2 \implies x = +2\) \(M^{2+}\) has 5 unpaired electrons. \(Mn^{2+}\) is \(3d^5\), which has 5 unpaired electrons (high spin). M = Mn
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