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CUET · CHEMISTRY · PYQ PAPER 2023

The spin-only magnetic moment of \(\left[ MBr _4\right]^{2-}\) is 5.9 BM.
The metal M is:

  1. A Fe
  2. B Cr
  3. C Mn
  4. D Co
Verified Solution

Answer & Solution

Correct Answer

(C) Mn

Step-by-step Solution

Detailed explanation

\(\mu_{spin} = \sqrt{n(n+2)}\) \(5.9 = \sqrt{n(n+2)} \implies n=5\) Oxidation state of M: \(x + 4(-1) = -2 \implies x = +2\) \(M^{2+}\) has 5 unpaired electrons. \(Mn^{2+}\) is \(3d^5\), which has 5 unpaired electrons (high spin). M = Mn
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