CUET · CHEMISTRY · PYQ PAPER 2025
The rate of a first order reaction is 0.06 mol \(L^{-1} s^{-1}\) after 20 seconds and 0.03 mol \(L^{-1} s^{-1}\) after 30 seconds from the start of the reaction. The half life period of this reaction is
- A 20 s
- B 30 s
- C 10 s
- D 0.30 s
Answer & Solution
Correct Answer
(B) 30 s
Step-by-step Solution
Detailed explanation
\( k = \frac{\ln(\text{Rate}_1/\text{Rate}_2)}{t_2 - t_1} \) \( k = \frac{\ln(0.06 \text{ mol L}^{-1} \text{ s}^{-1} / 0.03 \text{ mol L}^{-1} \text{ s}^{-1})}{30 \text{ s} - 20 \text{ s}} = \frac{\ln(2)}{10 \text{ s}} \) \( t_{1/2} = \frac{\ln(2)}{k} \)…
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