CUET · CHEMISTRY · PYQ PAPER 2023
The rate law for a reaction between substance P \& Q is given by
Rate = k[P]^x [Q]^y
If concentration of P is doubled and concentration of Q is halved, the ratio of the new rate to the earlier rate of reaction will be :
- A x+y
- B x-y
- C 2^-y
- D \(\frac{1}{2^{x-y}}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{2^{x-y}}\)
Step-by-step Solution
Detailed explanation
Initial Rate: \( Rate_1 = k[P]^x [Q]^y \) New Rate: \( Rate_2 = k(2[P])^x (\frac{1}{2}[Q])^y \) \( Rate_2 = k \cdot 2^x [P]^x \cdot 2^{-y} [Q]^y = k \cdot 2^{x-y} [P]^x [Q]^y \) Ratio of new rate to earlier rate:…
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