CUET · CHEMISTRY · PYQ PAPER 2025
The rate constant of a reaction increases from \(0.02 \mathrm{~s}^{-1}\) to \(0.04 \mathrm{~s}^{-1}\) when the temperature is raised from 500 K to 600 K.
The activation energy \(\left(E_a\right)\) of the reaction is
(Given: \(\log _{10} 2=0.3010\) )
- A \(0.170 \mathrm{cal} \mathrm{mol}^{-1}\)
- B \(17.289 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- C \(7.513 \mathrm{cal} \mathrm{mol}^{-1}\)
- D \(7.521 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(B) \(17.289 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\ln \left(\frac{k_2}{k_1}\right)=\frac{E_a}{R}\left(\frac{1}{T_1}-\frac{1}{T_2}\right)\) \(\ln \left(\frac{0.04}{0.02}\right)=\frac{E_a}{8.314}\left(\frac{1}{500}-\frac{1}{600}\right)\) \(\ln (2)=\frac{E_a}{8.314}\left(\frac{1}{500}-\frac{1}{600}\right)\)…
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