ExamBro
ExamBro
CUET · CHEMISTRY · PYQ PAPER 2023

The rate constant for the first order decomposition of \(H _2 O _2\) is given by:\[ \log k=15-\frac{1.2 \times 10^2}{T}\] The activation energy ( \(E_a\) ) would be:

  1. A 6 kJ
  2. B 2.3 kJ
  3. C 4.5 kJ
  4. D 3.2 kJ
Verified Solution

Answer & Solution

Correct Answer

(B) 2.3 kJ

Step-by-step Solution

Detailed explanation

\( \log k = \log A - \frac{E_a}{2.303 R T} \) \( \frac{E_a}{2.303 R} = 1.2 \times 10^2 \) \( E_a = 1.2 \times 10^2 \times 2.303 \times 8.314 \, J/mol \) \( E_a = 2307.696 \, J/mol \) \( E_a = 2.307696 \, kJ/mol \) \( E_a \approx 2.3 \, kJ \)
Same subject
Explore more questions on app
From CUET
Explore more questions on app