CUET · CHEMISTRY · PYQ PAPER 2023
The pressure of \(\text{H}_2\) required to make the potential of \(\text{H}_2\) electrode zero in pure water at 298 K is
(Given \(\text{E}_{cell} = 0.0 \text{ V}\))
- A \(10^{-4} \text{ atm}\)
- B \(10^{-14} \text{ atm}\)
- C \(10^{-12} \text{ atm}\)
- D \(10^{-10} \text{ atm}\)
Answer & Solution
Correct Answer
(B) \(10^{-14} \text{ atm}\)
Step-by-step Solution
Detailed explanation
\(E = E^\circ - \frac{0.0591}{n} \log \frac{P_{\text{H}_2}}{[\text{H}^+]^2}\) \(0 = 0 - \frac{0.0591}{2} \log \frac{P_{\text{H}_2}}{(10^{-7})^2}\) \(\log \frac{P_{\text{H}_2}}{10^{-14}} = 0\) \(P_{\text{H}_2} = 10^{-14} \text{ atm}\)
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