CUET · CHEMISTRY · PYQ PAPER 2023
The percentage dissociation of 0.1 M AgI solution having a resistance of 100 \(\Omega\) in an electrolytic cell with cell constant 4 \(\text{cm}^{-1}\) is:
\(\lambda_{\text{m}}^{\circ}\) \(\left( AgNO _3\right)\) = 8000 \(\Omega^{-1}\text{cm}^2\text{mol}^{-1}\)
\(\lambda_{\text{m}}^{\circ}\) \(\left( KNO _3\right)\) = 10500 \(\Omega^{-1}\text{cm}^2\text{mol}^{-1}\)
\(\lambda_{\text{m}}^{\circ}\) (KI) = 9500 \(\Omega^{-1}\text{cm}^2\text{mol}^{-1}\)
- A 5.7\(\%\)
- B 4.4\(\%\)
- C 11.4\(\%\)
- D 8.8\(\%\)
Answer & Solution
Correct Answer
(A) 5.7\(\%\)
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