CUET · CHEMISTRY · PYQ PAPER 2025
The Nernst equation corresponding to the cell reaction given below, is
Ni(s) + 2Ag\(^+\)(aq) \(\rightarrow\) Ni\(^2+\)(aq) + 2Ag(s)
- A \(E_{\text {cell }}=E_{\text {cell }}^{\circ}-\frac{R T}{2 F} \ln \frac{\left[\mathrm{Ni}^{2+}\right]}{\left[\mathrm{Ag}^{+}\right]^2}\)
- B \(E_{\text {cell }}=E_{\text {cell }}^{\circ}-\frac{R T}{2 F} \log \frac{\left[\mathrm{Ni}^{2+}\right]}{\left[\mathrm{Ag}^{+}\right]^2}\)
- C \(E_{\text {cell }}=E_{\text {cell }}^{\circ}-\frac{R T}{2 F} \ln \frac{\left[\mathrm{Ni}^{2+}\right]}{2\left[\mathrm{Ag}^{+}\right]^2}\)
- D \(E_{\text {cell }}=E_{\text {cell }}^{\circ}-\frac{R T}{F} \ln \frac{\left[\mathrm{Ni}^{2+}\right][\mathrm{Ag}]^2}{\left[\mathrm{Ag}^{+}\right]^2[\mathrm{Ni}]}\)
Answer & Solution
Correct Answer
(A) \(E_{\text {cell }}=E_{\text {cell }}^{\circ}-\frac{R T}{2 F} \ln \frac{\left[\mathrm{Ni}^{2+}\right]}{\left[\mathrm{Ag}^{+}\right]^2}\)
Step-by-step Solution
Detailed explanation
\( n = 2 \) \( Q = \frac{\left[\mathrm{Ni}^{2+}\right]}{\left[\mathrm{Ag}^{+}\right]^2} \) \( E_{\text {cell }}=E_{\text {cell }}^{\circ}-\frac{R T}{2 F} \ln \frac{\left[\mathrm{Ni}^{2+}\right]}{\left[\mathrm{Ag}^{+}\right]^2} \)
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