CUET · CHEMISTRY · PYQ PAPER 2025
The molar conductivity of KNO\(_3\), NaCl and KCl are 111, 128 and 152 S cm\(^2\) mol\(^-\)\(\mathrm{^1}\), respectively. The molar conductivity of NaNO\(_3\) will be:
- A 101 S cm\(^2\) mol\(^-\)\(\mathrm{^1}\)
- B 391 S cm\(^2\) mol\(^-\)\(\mathrm{^1}\)
- C -391 S cm\(^2\) mol\(^-\)\(\mathrm{^1}\)
- D 87 S cm\(^2\) mol\(^-\)\(\mathrm{^1}\)
Answer & Solution
Correct Answer
(D) 87 S cm\(^2\) mol\(^-\)\(\mathrm{^1}\)
Step-by-step Solution
Detailed explanation
\( \Lambda_m(\mathrm{NaNO_3}) = \Lambda_m(\mathrm{KNO_3}) + \Lambda_m(\mathrm{NaCl}) - \Lambda_m(\mathrm{KCl}) \) \( = 111 + 128 - 152 \) \( = 87 \text{ S cm}^2 \text{ mol}^{-1} \)
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