CUET · CHEMISTRY · PYQ PAPER 2025
The molality of solution obtained by dissolving 1.5 g of ethanoic acid \(CH _3 COOH\) in \(2 5 ~ g\) of benzene is :
- A \(0.1 mol kg ^{-1}\)
- B \(0.001 mol kg ^{-1}\)
- C \(1.0 mol kg ^{-1}\)
- D \(0.2 mol kg ^{-1}\)
Answer & Solution
Correct Answer
(C) \(1.0 mol kg ^{-1}\)
Step-by-step Solution
Detailed explanation
\(M_{CH_3COOH} = 2(12.01) + 4(1.01) + 2(16.00) = 60.06 \text{ g/mol}\) \(n_{CH_3COOH} = \frac{1.5 \text{ g}}{60.06 \text{ g/mol}} = 0.02497 \text{ mol}\) \(m_{benzene} = 25 \text{ g} = 0.025 \text{ kg}\)…
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