CUET · CHEMISTRY · PYQ PAPER 2023
The mass of urea (\(NH_2CONH_2\)) required to make 2.5 kg of 0.25 molal aqueous solution will be :
- A 39 g
- B 38 g
- C 37.5 g
- D 36.5 g
Answer & Solution
Correct Answer
(C) 37.5 g
Step-by-step Solution
Detailed explanation
\( M_{NH_2CONH_2} = 2 \times 14 + 4 \times 1 + 1 \times 12 + 1 \times 16 = 60 \, \text{g/mol} \) \( n_{urea} = m \times W_{solvent} \) \( n_{urea} = 0.25 \, \text{mol/kg} \times 2.5 \, \text{kg} = 0.625 \, \text{mol} \) \( W_{urea} = n_{urea} \times M_{urea} \)…
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