CUET · CHEMISTRY · PYQ PAPER 2023
The \(\Lambda_m^{\circ}\) for \(CaSO _4\) at 298 K , if \(\lambda_{ Ca ^{+2}}^{\circ}=119.0 Scm ^2 mol^{-1}\) and \(\lambda_{ SO _4^{2-}}^{\circ}=160.0 Scm ^2 mol^{-1}\) will be:
- A \(558 Scm ^2 mol^{-1}\)
- B \(139.5 Scm ^2 mol^{-1}\)
- C \(69.75 Scm ^2 mol^{-1}\)
- D \(279 Scm ^2 mol^{-1}\)
Answer & Solution
Correct Answer
(D) \(279 Scm ^2 mol^{-1}\)
Step-by-step Solution
Detailed explanation
\(\Lambda_m^{\circ}(CaSO_4) = \lambda_{ Ca ^{+2}}^{\circ} + \lambda_{ SO _4^{2-}}^{\circ}\) \(\Lambda_m^{\circ}(CaSO_4) = 119.0 + 160.0\) \(\Lambda_m^{\circ}(CaSO_4) = 279.0 Scm ^2 mol^{-1}\)
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