CUET · CHEMISTRY · PYQ PAPER 2025
The limiting molar conductivities for \(NaCl\), \(HCl\) and \(CH_3COONa\) are \(126.4\), \(425.9\) and \(91.0\ S\ cm^2\ mol^{-1}\), respectively. Calculate the limiting molar conductivity for acetic acid.
- A \(390.5\ S\ cm^2\ mol^{-1}\)
- B \(208.5\ S\ cm^2\ mol^{-1}\)
- C \(461.3\ S\ cm^2\ mol^{-1}\)
- D \(643.3\ S\ cm^2\ mol^{-1}\)
Answer & Solution
Correct Answer
(A) \(390.5\ S\ cm^2\ mol^{-1}\)
Step-by-step Solution
Detailed explanation
\(\Lambda^0_m(CH_3COOH) = \Lambda^0_m(CH_3COONa) + \Lambda^0_m(HCl) - \Lambda^0_m(NaCl)\) \(\Lambda^0_m(CH_3COOH) = 91.0 + 425.9 - 126.4\) \(\Lambda^0_m(CH_3COOH) = 390.5 S \ cm^2 \ mol^{-1}\)
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