CUET · CHEMISTRY · PYQ PAPER 2023
The half life for radioactive decay of C-14 is 5730 years.
A sample of tree had only 80% of C-14 left.
Estimate the age of the tree.
(log 5 = 0.698) (log 4 = 0.602)
- A Approx. 1400 years
- B Approx. 1600 years
- C Approx. 1800 years
- D Approx. 2000 years
Answer & Solution
Correct Answer
(C) Approx. 1800 years
Step-by-step Solution
Detailed explanation
\( \frac{N}{N_0} = (\frac{1}{2})^{\frac{t}{T}} \) \( 0.8 = (0.5)^{\frac{t}{5730}} \) \( t = 5730 \times \frac{\log(0.8)}{\log(0.5)} \) \( \log(2) = \frac{\log(4)}{2} = \frac{0.602}{2} = 0.301 \)…
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