CUET · CHEMISTRY · PYQ PAPER 2025
The degree of dissociation ( \(\alpha\) ) of a weak electrolyte \(A_x B_y\) is related to the van't Hoff factor (i) by the expression:
- A \(\alpha=\frac{(i-1)}{(x+y-1)}\)
- B \(\alpha=\frac{(i-1)}{(x+y+1)}\)
- C \(\alpha=\frac{(x+y-1)}{(i-1)}\)
- D \(\alpha=\frac{(x+y+1)}{(i-1)}\)
Answer & Solution
Correct Answer
(A) \(\alpha=\frac{(i-1)}{(x+y-1)}\)
Step-by-step Solution
Detailed explanation
\(i = 1 + (n-1)\alpha\) \(i = 1 + (x+y-1)\alpha\) \(\alpha = \frac{(i-1)}{(x+y-1)}\)
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