CUET · CHEMISTRY · PYQ PAPER 2023
The decomposition of \(NH_3\) on platinum surface is a zero order reaction. The rates of production of \(N_2\) and \(H_2\) respectively are : (in \(mol^{-1}Ls^{-1}\)) Given that \(2.5 \times 10^{-4}\text{ mol}^{-1}\text{L s}^{-1}\) is the rate of reaction.
- A \(2.5 \times 10^{-4}, 2.5 \times 10^{-4}\)
- B \(7.5 \times 10^{-4}, 2.5 \times 10^{-4}\)
- C \(2.5 \times 10^{-4}, 7.5 \times 10^{-4}\)
- D \(7.5 \times 10^{-4}, 7.5 \times 10^{-4}\)
Answer & Solution
Correct Answer
(C) \(2.5 \times 10^{-4}, 7.5 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
\(2NH_3(g) \rightarrow N_2(g) + 3H_2(g)\) \(Rate = \frac{d[N_2]}{dt} = \frac{1}{3}\frac{d[H_2]}{dt}\) \(\frac{d[N_2]}{dt} = 2.5 \times 10^{-4} \text{ mol L}^{-1}\text{s}^{-1}\)…
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